返回榜单
Seven Knights Re:BIRTH

Seven Knights Re:BIRTH

Netmarble Corporation

Games免费v1.21.03
App Store
评分

4.8

3,573 条评分

星级

★★★★★

最近更新

2026年5月13日

发布日期

2025年9月16日

更新内容

v1.21.03

[New Additions] - New Legendary Hero [Karl Heron] added. - 1st Anniversary Festival underway. - 7 new Rare Costumes added. [Improvements and Fixes] - Improved content convenience. - Bug fixes and other improvements.

应用信息

开发者
Netmarble Corporation
分类
Games
价格
免费
版本
1.21.03
App ID
6479595079

简介

100 Million Hearts, A Legacy Reborn! Auto turn-based battles, bold skill action, and the story of The Evan Expedition's adventure. The original game has been reborn! ≪ Game Introduction ≫ Do you remember playing the original Seven Knights game with your friends? Welcome to Seven Knights Re:BIRTH: a game that will fill you with the same thrill and emotions. Featuring: ▶ A [Refined Turn-Based Battle System] Strategically set your team formation and skill order, and you're ready to go! Sit back and watch the battle unfold! ▶ A [Bold Visual RPG] with the signature vibrance of the Seven Knights Watch charming heroes unleash their skills before you; from the beautiful Lunar Slash to the breathtaking Meteor Wrecker. ▶ Experience diverse cinematics from the [Seven Knights Hero Story] See the colorful heroes like never before in new animations and illustrations. ▶ Play for FREE and farm Rubies to get opportunities to Summon [Daily Excitement] Play to obtain Rubies and use them to summon heroes! Enter a world of sustainable hero collecting: a true collectible RPG! ※ This app offer in-app purchases. You can disable this feature by adjusting your device’s settings. By downloading this game, you are agreeing to our Terms of Service and Privacy Policy. - Terms of Use: https://help.netmarble.com/en/terms/terms_of_service_en - Privacy Policy: https://help.netmarble.com/en/terms/privacy_policy_en

下载量预测

专业 · 预览

预估总下载量

179K119K357K
保守估计乐观估计

15K

低 / 月

22K

预估 / 月

45K

高 / 月

基于3,573 条评分
假设评分率2.0%
应用年龄8 个月

基于评分数量 ÷ 类别评分率估算,实际下载量误差可达 ±50%,与 Sensor Tower 方法一致。