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Word Sort Fun!

Word Sort Fun!

Oakever Games

Games免费v1.14.2
App Store
评分

4.6

10 条评分

星级

★★★★★

最近更新

2026年4月27日

发布日期

2024年1月12日

更新内容

v1.14.2

Fixed known issues.

应用信息

开发者
Oakever Games
分类
Games
价格
免费
版本
1.14.2
App ID
6474589614

简介

Word Sort Fun! – A Fresh Twist on Cards, Words, and Brainy Fun Step into Word Sort Fun!, where relaxing card-play and engaging word challenges come together in one delightful experience. Build smart connections, sort clues, and clear each board with thoughtful moves. Whether you have a few spare minutes or want a longer mind-training session, this game is made to fit your rhythm. Features of Word Sort Fun! 1. A huge collection of handcrafted word levels to sharpen thinking and language skills. 2. A unique gameplay mix that combines card strategy with word-solving mechanics. 3. No countdown pressure — enjoy every round at a calm, comfortable pace. 4. Plan each move carefully to unlock better outcomes and complete tricky boards. 5. Play anywhere with offline support, even without an internet connection. How to Play 1. Start by placing category cards onto the board. 2. Draw word and image cards from the deck. 3. Match and organize cards based on logic and associations. 4. Clear the board before you run out of available moves to win the level. Why Choose Word Sort Fun! 1. Satisfying puzzle progression that keeps each stage interesting. 2. A relaxing but rewarding challenge for both casual and dedicated players. 3. Strategic gameplay that improves focus, memory, and problem-solving. 4. Suitable for all ages and experience levels. 5. Download Word Sort Fun! today and discover a relaxing way to train your brain with creative word-card puzzles anytime, anywhere. Privacy Policy: https://oakevergames.com/pp.html Terms of Service: https://oakevergames.com/tos.html EULA: https://www.apple.com/legal/internet-services/itunes/dev/stdeula/

下载量预测

专业 · 预览

预估总下载量

5003331K
保守估计乐观估计

11

低 / 月

17

预估 / 月

34

高 / 月

基于10 条评分
假设评分率2.0%
应用年龄29 个月

基于评分数量 ÷ 类别评分率估算,实际下载量误差可达 ±50%,与 Sensor Tower 方法一致。